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linux - "awk with if / substr " didn't work as expected - Unix & Linux...
I want to filter the records where disk usage is greater than 70% using df and awk/if/substr.
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Здравствуйте, не могу решить проблему с записью value в вар. Вот скрипт.
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javascript - Display only a part of the name if... - Stack Overflow
You can use substr() method to get part of the name: var namePart = this.username.substr(0, 8) + '..'; Or you can use CSS overflow: hidden; and text-overflow: ellipsis; properties: demo.
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